Lessons learned today: There are still operators in C++ I did not know \ud83d\ude42<\/p>\n
I was suprised when I saw these strange operators ->*<\/b> and .*<\/b>.<\/p>\n
You can use those operators when you have a pointer to a member function. In order to call this function, you need an explicit instance. ->*<\/b> and .*<\/b> combines function pointer and instance. .*<\/b> is a built-in operator and cannot be overloaded. ->*<\/b> may be overloaded.<\/p>\n More on this<\/a><\/p>\n","protected":false},"excerpt":{"rendered":" Lessons learned today: There are still operators in C++ I did not know \ud83d\ude42 I was suprised when I saw these strange operators ->* and .*. You can use those operators when you have a pointer to a member function. In order to call this function, you need an explicit instance. ->* and .* combines … Continue reading C++’s “pointer-to-member” operator<\/span> \r\nclass A\r\n{\r\npublic:\r\n void f() {}\r\n void g() {}\r\n};\r\n\r\n\r\n...\r\n\r\nvoid (A::*ptr)(); \/\/ This is a pointer to a member function of A\r\n\r\n\/\/ Let the pointer point to f\r\nptr = &A::f;\r\n\/\/ We cannot use this pointer without an object\r\nA a;\r\n(a.*ptr)() \/\/ Call f on instance a\r\n\/\/ Now we have a pointer to an instance\r\nA *b = new A;\r\n(b->*ptr)() \/\/ Call f on instance b\r\n<\/pre>\n